4p^2=25p-25

Solution for 4p^2=25p-25 equation:

4p^2=25p-25

We move all terms to the left:

4p^2-(25p-25)=0

We get rid of parentheses

4p^2-25p+25=0

a = 4; b = -25; c = +25;
Δ = b2-4ac
Δ = -252-4·4·25
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-15}{2*4}=\frac{10}{8}
=1+1/4
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+15}{2*4}=\frac{40}{8}
=5
$